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Question

A conductor of mass m and length l is placed perpendicular to a horizontal uniform magnetic field B. Suddenly, a certain amount of charge is passed through it, and it is found to jump to a height h. The amount of charge that passes through the conductor is -

A
mghBl
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B
2mghBl
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C
m2ghBl
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D
None of these
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Solution

The correct option is C m2ghBl

We know that,

Impulse = Change in momentum

FΔt=m2gh {v2=u2+2ghor v2=2gh}

BIlΔt=m2gh [F=BIl]

IΔt=m2ghBl

Δq=m2ghBl {I=ΔqΔt}

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, option (C) is the correct answer.

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