Question

A conductor of resistance $3\Omega$ is moving with speed v = 6 m/s. B is uniform & is equal to 4 Tesla. Length of the conductor is 50 cm. If $R=5\Omega$, find the power dissipated in $5\Omega$.

• A. 6 Watt
• B. 15 Watt
• C. 9 Watt
• D. 11 Watt

Answer 1

The correct option is D 11 Watt

$i=\frac{Bvl}{r+R}=\frac{\left(4\right)\left(6\right)\left(\frac{1}{2}\right)}{3+5}=\frac{12}{8}=1.5A$
$P=i^{2}R=1.5\times 1.5\times 5=\frac{3\times 3\times 5}{4}=\frac{45}{4}\simeq 11Watt$