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Question

A conductor of resistance 3Ω is moving with speed v = 6 m/s. B is uniform & is equal to 4 Tesla. Length of the conductor is 50 cm. If R=5Ω, find the power dissipated in 5Ω.


A
6 Watt
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B
15 Watt
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C
9 Watt
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D
11 Watt
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Solution

The correct option is D 11 Watt
i=Bvlr+R=(4)(6)(12)3+5=128=1.5 A
P=i2R=1.5×1.5×5=3×3×54=45411 Watt

Physics

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