A conductor of uniform cross section and 60m long has a voltage drop of 1-2 V and a current densityof 2-56- 105 A-m2- The conductivity of the material in the conductor is - 104 S-m

According to the Ohm’s law, J= σ E Here, J= 2.56 × 10^5 A/m^2 E= Vl =1.260 = 0.02 V/m Conductivity of material , σ =JE =2.56 × 10^50.02 = 128 × 10^5 S/m ...

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Standard IX

Physics

Resistivity

A conductor o...

Question

A conductor of uniform cross section and 60m long has a voltage drop of 1.2 V and a current densityof $2.56 \times 10^{5} A / m^{2}$ . The conductivity of the material in the conductor is___ $\times 10^{4} S / m$
1.28

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Solution

The correct option is A 1.28
According to the Ohm’s law,

$J = σ E$

Here, $J = 2.56 \times 10^{5} A / m^{2}$

$E = \frac{V}{l} = \frac{1.2}{60} = 0.02 V / m$

Conductivity of material ,

$σ = \frac{J}{E} = \frac{2.56 \times 10^{5}}{0.02} = 128 \times 10^{5} S / m$

$= 1.28 \times 10^{7} S / m$

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A conductor of uniform cross section and 60m long has a voltage drop of 1.2 V and a current densityof 2.56×105A/m2. The conductivity of the material in the conductor is___ ×104S/m 1.28

The correct option is A 1.28According to the Ohm’s law, J=σE Here, J=2.56×105A/m2 E=Vl=1.260=0.02 V/m Conductivity of material , σ=JE=2.56×1050.02=128×105S/m =1.28×107S/m

A conductor of uniform cross section and 60m long has a voltage drop of 1.2 V and a current densityof $2.56 \times 10^{5} A / m^{2}$ . The conductivity of the material in the conductor is___ $\times 10^{4} S / m$
1.28

The correct option is A 1.28
According to the Ohm’s law,

$J = σ E$

Here, $J = 2.56 \times 10^{5} A / m^{2}$

$E = \frac{V}{l} = \frac{1.2}{60} = 0.02 V / m$

Conductivity of material ,

$σ = \frac{J}{E} = \frac{2.56 \times 10^{5}}{0.02} = 128 \times 10^{5} S / m$

$= 1.28 \times 10^{7} S / m$