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Question

A conductor with a cavity is charged positively and its surface charge density is σ. If E and V represent the electric field and potential, then inside the cavity:

A
and V=0
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B
E=0 and V=0
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C
E=0 and σ=constant
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D
V=0 and σ= constant
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E
E=0 and V= constant
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Solution

The correct option is E E=0 and V= constant
Surface charge density =σ.
Inside the surface, the electric field is zero.
Einside=0
Vinside=Vsurface
The potential inside the surface of charged sphere is constant.
E=0,V=constant.

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