A conductor with a cavity is charged positively and its surface charge density is σ. If E and V represent the electric field and potential, then inside the cavity:
A
and V=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
E=0 and V=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
E=0 and σ=constant
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
V=0 and σ= constant
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
E=0 and V= constant
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is EE=0 and V= constant Surface charge density =σ. Inside the surface, the electric field is zero. ⇒Einside=0 ∵Vinside=Vsurface The potential inside the surface of charged sphere is constant. ∴E=0,V=constant.