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Question

# A conductor with rectangular cross-section has dimensions (a×2a×4a) as shown in figure. Resistance across AB is R1, across CD is R2 and across EF is R3. Then which of the following is true?

A
R1=R2=R3
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B
R1 > R2 > R3
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C
R2 > R3 > R1
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D
R1 > R3 > R2
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Solution

## The correct option is B R1 > R2 > R3 Resistance R=ρlA From the figure the dimensions are a, 2a and 4a, i.e. Distance between faces A and B = 4a Distance between faces C and D= 2a Distance between faces E and F= a As R∝l, AB having the highest length will have the most resistance followed by CD and EF being of the lowest length will have the least resistance. So, the order is R1>R2>R3.

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