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Shape Conversion of Solids

A conical fla...

Question

A conical flask is full of water. The flask has base-radius $r$ and height $h$ . The water is poured into a cylindrical flask of base-radius $m r$ . Find the height of water in the cylindrical flask.

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Solution

$\frac{1}{3} π r^{2} h = π (m r)^{2} H$

$H = \frac{h}{3 m^{2}}$

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