Question

A conical pendulum of length L makes an angle with the vertical as shown in the figure. The time period will be

• A. $2\pi \sqrt{\frac{Lcos\theta }{g}}$
• B. $2\pi \sqrt{\frac{L}{gcos\theta }}$
• C. $2\pi \sqrt{\frac{Ltan\theta }{g}}$
• D. $2\pi \sqrt{\frac{L}{gtan\theta }}$

Answer 1

The correct option is A $2\pi \sqrt{\frac{Lcos\theta }{g}}$

Time period of conical pendulum is written as,
$T=2\pi \sqrt{\frac{L}{g}}$
$L_{vertical}=Lcos\theta$
$T=2\pi \sqrt{\frac{Lcos\theta }{g}}$