A conical tent has radius $8.4 m$ and vertical height $3.5 m$ . How many full bags of wheat can be emptied if the space occupied by each bag of wheat is $1.96 m^{3}$ .

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Solution

Radius of conical tent $= 8.4 m$
Height of the tent $= 3.5 m$
Volume of the conical tent $= \frac{1}{3} π r^{2} h$
$= \frac{6468}{25} m^{3}$

Volume of bag $= 1.96 m^{3}$
Number of bags can be emptied $=$ Volume of tent $\div$ Volume of bag
$= \frac{\frac{6468}{25}}{1.96} = 132$

Therefore,
$132$ bags of wheat can be emptied to fill the tent.

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A conical tent has radius 8.4 m and vertical height 3.5 m. How many full bags of wheat can be emptied if the space occupied by each bag of wheat is 1.96m3.

Radius of conical tent =8.4 mHeight of the tent =3.5 mVolume of the conical tent =13πr2h =646825 m3Volume of bag =1.96 m3Number of bags can be emptied = Volume of tent ÷ Volume of bag=6468251.96=132Therefore,132 bags of wheat can be emptied to fill the tent.

A conical tent has radius $8.4 m$ and vertical height $3.5 m$ . How many full bags of wheat can be emptied if the space occupied by each bag of wheat is $1.96 m^{3}$ .