A conical tent is $10 m$ high and the radius of its base is $24 m$ . Find cost of the canvas required to make the tent, if the cost of $1 m^{2}$ canvas is $R s 70$ .

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Solution

Given height of conical tent $= 10$ m.
radius of its base $= 24$ m.
now
CSA of conical tent = $π r l = π r [\sqrt{r^{2} + h^{2}}]$
CSA of conical tent = $3.14 \times 24 \sqrt{(24)^{2} + (10)^{2}}$
CSA of cone $= 1960.35$ cm $^{2}$

Cost of canvas required = $70 R s / m^{2}$
Total cost of canvas required = $70 \times 1959.36$
Total cost $= 137224.77$ Rs.

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Similar questions

A conical tent 10 m high and tha radius of its base is 24 m . Find the slant height of the rent. If the cost of $1 m^{2}$ canvas is Rs70, find the cost of canvas required to make the tent.

Q. Note Use

π = \frac{22}{7}

, unless stated otherwise.
A conical tent is 10 m high and the radius of its base is 24 m. Find the slant height of the tent. If the cost of 1 m² canvas is ₹ 70, find the cost of canvas required to make the tent.

Q. Question 4
A conical tent is 10 m high and the radius of its base is 24 m. Find
(i) Slant height of the tent.
(ii) Cost of the canvas required to make the tent, if the cost of

1 m^{2}

canvas is Rs 70.

[A s s u m e π = \frac{22}{7}]

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A conical tent is 10 m high and the radius of its base is 24 m. Find cost of the canvas required to make the tent, if the cost of 1 m2 canvas is Rs 70.

Given height of conical tent =10 m.radius of its base =24 m.now CSA of conical tent = πrl=πr[√r2+h2]CSA of conical tent = 3.14×24√(24)2+(10)2CSA of cone =1960.35 cm2Cost of canvas required = 70Rs/m2Total cost of canvas required = 70×1959.36Total cost =137224.77 Rs.

A conical tent is $10 m$ high and the radius of its base is $24 m$ . Find cost of the canvas required to make the tent, if the cost of $1 m^{2}$ canvas is $R s 70$ .