A conical tent is 10 m high and the radius of its base is 24 m.Find the slant height of the tent.If the cost of 1 $m^{2}$ canvas is Rs.70,find the cost of the canvas required to make the tent.

Open in App

Solution

Height of conical tent (h)=10 m

Radius of the base (r)=24 m

(i) $∴ S l a n t h e i g h t (l) = \sqrt{r^{2} + h^{2}} = \sqrt{(24)^{2} + (10)^{2}} = \sqrt{576 + 100} = \sqrt{676} l = 26 m$

(ii) Now area of the conical tent = $π r l$
$= \frac{22}{7} \times 24 \times 26 m^{2} R a t e o f 1 m^{2} c o n v a s u s e d = R s .70 ∴ T o t a l C o s t o f t h e t e n t = \frac{22}{7} \times 24 \times 26 \times 70 = R s .137280$
Hence, cost of the canvas required to make the tent is $1, 37, 280$ RS.

Suggest Corrections

241

Similar questions

1 m^{2}

[A s s u m e π = \frac{22}{7}]

π = \frac{22}{7}

10 m

24 m

1 m^{2}

R s 70

Join BYJU'S Learning Program