A conical tomb is made up of bricks of a front surface area of 5 square meters.The slant height and radius of the tomb are measured to be 25 m and 7 m respectively. The approximate number of bricks made used to construct the tomb are ___ (Take $π = \frac{22}{7}$ )

100

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110

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150

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160

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Solution

The correct option is B
110

Slant height l = 25

Radius r = 7

Curved surface area of the tomb = $π r l$
$= \frac{22}{7} \times 7 \times 25$
$= 550 m^{2}$

So, number of bricks required $= \frac{C u r v e d S u r f a c e A r e a o f t o m b}{L a t e r a l S u r f a c e A r e a o f b r i c k s}$
$= \frac{550}{5} = 110$ bricks

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A conical tomb is made up of bricks of a front surface area of 5 square meters.The slant height and radius of the tomb are measured to be 25 m and 7 m respectively. The approximate number of bricks made used to construct the tomb are ___ (Take π=227)

The correct option is B 110 Slant height l = 25 Radius r = 7 Curved surface area of the tomb = πrl =227×7×25 =550m2 So, number of bricks required =Curved Surface Area of tombLateral Surface Area of bricks =5505=110 bricks

A conical tomb is made up of bricks of a front surface area of 5 square meters.The slant height and radius of the tomb are measured to be 25 m and 7 m respectively. The approximate number of bricks made used to construct the tomb are ___ (Take $π = \frac{22}{7}$ )