A conical tomb is made up of bricks of a front surface area of $5$ sq. m. The slant height and radius of the tomb are measured to be $25 m$ and $7 m$ respectively. The approximate number of bricks used to construct the tomb are ___ $(Take π = \frac{22}{7})$

100

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110

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150

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160

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Solution

The correct option is B
110

Slant height, $l = 25$

Radius, $r = 7$

Curved Surface area of the tomb $= π r l$
$= \frac{22}{7} \times 7 \times 25$
$= 550 m^{2}$

So, number of bricks required $= \frac{Curved Surface Area of tomb}{Lateral Surface Area of bricks}$
$= \frac{550}{5} = 110$ bricks

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A conical tomb is made up of bricks of a front surface area of 5 sq. m. The slant height and radius of the tomb are measured to be 25 m and 7 m respectively. The approximate number of bricks used to construct the tomb are ___ (Take π=227)

The correct option is B 110 Slant height, l=25 Radius, r=7 Curved Surface area of the tomb =πrl =227×7×25 =550 m2 So, number of bricks required =Curved Surface Area of tombLateral Surface Area of bricks =5505=110 bricks

A conical tomb is made up of bricks of a front surface area of $5$ sq. m. The slant height and radius of the tomb are measured to be $25 m$ and $7 m$ respectively. The approximate number of bricks used to construct the tomb are ___ $(Take π = \frac{22}{7})$

The correct option is B
110

Slant height, $l = 25$

Radius, $r = 7$

Curved Surface area of the tomb $= π r l$
$= \frac{22}{7} \times 7 \times 25$
$= 550 m^{2}$

So, number of bricks required $= \frac{Curved Surface Area of tomb}{Lateral Surface Area of bricks}$
$= \frac{550}{5} = 110$ bricks