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Question

A constant current(0.5 amp) is passed for 1 hour through (i) aqueous AgNO3, (ii) aqueous CuSO4 and (iii) molten AlF3, separately. The ratio of the mass of the metals deposited on the cathode is? [MAg,MCu,MAl are molar masses of the respective metals].

A
MAg:2MCu:3MAl
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B
MAg:MCu:MAl
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C
6MAg:3MCu:2MAl
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D
3MAg:2MCu:MAl
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Solution

The correct option is C 6MAg:3MCu:2MAl
The ratio of the mass of metal deposited is directly proportional to their equivalent weights.

AgNO3Ag++NO3
Equivalent weight of AgNO3=MAg

CuSO4Cu2++SO24
Equivalent weight of CuSO4=MCu2

AlF3Al3++3F
Equivalent weight of AlF3=MAl3

So, the ratio of the mass of metal deposited on the cathode is: 6MAg:3MCu:2MAl

Hence, option C is correct.

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