A constant electric current flows for $4$ hours through two electrolytic cells connected in series. One contain $A g N O_{3}$ solution and second contains $C u C l_{2}$ solution. During this time, $4$ grams of Ag are deposited in the first cell.
What is the current flowing in amperes?

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Solution

$W = Z . i . t$
$\Rightarrow 4 = \frac{E}{F} \times i \times 4 \times 3600 s e c$
$i = (\frac{4 \times 96500 \times 1}{4 \times 3600 \times 108}) = 0.248 A m p$

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