Question

A constant force acting on a body of mass $3kg$ changes its speed from $2m/s$ to $3.5m/s$ in $25s$. In the direction of the motion of the body what is the magnitude and direction of the force.

Answer 1

$v_i=2m/s$ $t=25s$

$v_f=3.5m/s$

$a=\frac{F}{3}$

$v_f=v_i+at$

$3.5=2+\left(25\right)\frac{F}{3}$

$\frac{1.5\ast 3}{25}=F$

$\frac{4.5}{25}=F$

$F=0.18N$