A constant force acts on a body of mass $0.9 k g$ at rest for $10 s$ . If the body moves a distance of $250 m,$ the magnitude of the force is :

3 N

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3.5 N

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4 N

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4.5 N

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Solution

The correct option is D $4.5 N$

By using the equation

$S = u t + \frac{1}{2} a t^{2}$

As the initial velocity is zero

By substituting the values we get

$250 = 50 a$

The acceleration is $5 \frac{m}{{sec}^{2}}$

We know that

$F = m \times a$

We get

$F = 0.9 \times 5$

Hence the force is $4.5 N$

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A constant force acts on a body of mass 0.9kg at rest for 10s . If the body moves a distance of 250m, the magnitude of the force is :

The correct option is D 4.5N By using the equation S=ut+12at2 As the initial velocity is zero By substituting the values we get 250=50a The acceleration is5msec2 We know that F=m×a We get F=0.9×5 Hence the force is4.5N

A constant force acts on a body of mass $0.9 k g$ at rest for $10 s$ . If the body moves a distance of $250 m,$ the magnitude of the force is :