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Standard X

Physics

Newton's Second Law: Rotatory Version

A constant fo...

Question

A constant force 'F' is applied at the top of a ring as shown in figure. Mass of the ring is 'M' and radius is 'R'. Angular momentum of particle about point of contact at time 't' is

Is constant

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Increases linearly with time

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Is Zero

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Decreases linearly with time

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Solution

The correct option is B Increases linearly with time
Angular impulse = change in angular momentum
we have L = $τ$ * t
or, L = F(2R)t
i.e. L increases linearly with time.

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A constant force 'F' is applied at the top of a ring as shown in figure. Mass of the ring is 'M' and radius is 'R'. Angular momentum of particle about point of contact at time 't' is

The correct option is B Increases linearly with timeAngular impulse = change in angular momentum we have L = τ * t or, L = F*(2R)*t i.e. L increases linearly with time.

The correct option is B Increases linearly with time
Angular impulse = change in angular momentum
we have L = $τ$ * t
or, L = F(2R)t
i.e. L increases linearly with time.