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Standard XII

Physics

SHM expression

A constant fo...

Question

A constant force $F$ is applied on a body of mass $5 k g$ , changes its velocity from $2 m / s$ to $7 m / s$ in $10 s$ . If the direction of motion is unchanged, then the $F$ is :

5 N

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7.5 N

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2.5 N

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10 N

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Solution

The correct option is C $2.5 N$
Mass $= 5 k g$ ,

Acceleration $= \frac{V_{2} {- V}_{1}}{t} = \frac{7 - 2}{10} = 0.5 m / s^{2}$

So, $F = M \times a = 5 \times 0.5 = 2.5 N$

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A constant force F is applied on a body of mass 5 kg, changes its velocity from 2 m/s to 7 m/s in 10 s. If the direction of motion is unchanged, then the F is :

The correct option is C 2.5 NMass =5 kg, Acceleration =V2−V1t=7−210=0.5 m/s2So, F=M×a=5×0.5=2.5 N

A constant force $F$ is applied on a body of mass $5 k g$ , changes its velocity from $2 m / s$ to $7 m / s$ in $10 s$ . If the direction of motion is unchanged, then the $F$ is :

The correct option is C $2.5 N$
Mass $= 5 k g$ ,

Acceleration $= \frac{V_{2} {- V}_{1}}{t} = \frac{7 - 2}{10} = 0.5 m / s^{2}$

So, $F = M \times a = 5 \times 0.5 = 2.5 N$