Question

A constant force of 12 N is acting on an object. Under its influence, the object is displaced through 5 m in the direction of the force. What is the work done by the force on the object?

Answer 1

1. Given the force acting on the object (F) = 12 N
Displacement in the direction of the force (s) =5 m
Let W is the work done by the force F on the object.
2. Work is said to be done on an object by a force if the object moves a certain distance.
Work done can be calculated as-
$$\begin{gathered} W=\left(F\cos \theta \right)\times s \\ HereW=worddone\left(j\right) \\ F=forceapplied\left(N\right) \\ s=displacement\left(m\right) \\ \theta =anglebetweenFands \end{gathered}$$----------------------------- (I)
3. Substituting the value of F, s, and cos$\theta$ in equation (I).
$$\begin{gathered} W=12\cos 0^{°}\times 5 \\ S\mathrm{in}ce\cos \theta =0°=1(Fandsareinsamedirection) \\ W=12\times 5 \\ orW=60J \end{gathered}$$
Hence the work done by the force on the object is 60J