A constant force of 5 N is acting on a body. If x(t) is the dispacement at time t, v(t) velocity at time t, m mass of the body, which of the following differential equations represent the situation?
A
mdx(t)dt=5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
mdv(t)dt=5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
md2x(t)dt2=5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
5dx(t)dt=m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct options are Bmdv(t)dt=5 Cmd2x(t)dt2=5 Using the second law of motion F=ma, and acceleration a is the rate of change of velocity i.e. a=dv(t)dt and velocity is the rate of change of displacement i.e. v=dx(t)dt. So a=dvdt=ddt(dxdt)=d2xdt2