A constant force →F=2^i−3^j+^k is applied on a ball to displace it from →r1=^i+^j to →r2=4^i+3^j, which of the following statements is true?
A
Force and displacement are perpendicular to each other and work done by force is equal to zero
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B
Force and displacement are parallel to each other and work done by force is equal to zero
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C
Force and displacement are anti parallel to each other and work done by force is equal to zero
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D
Force and displacement are perpendicular to each other and work done by force is not equal to zero
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Solution
The correct option is A Force and displacement are perpendicular to each other and work done by force is equal to zero Given constant force →F=(2^i−3^j+^k)N Initial position →r1=(^i+^j)m Final position →r2=(4^i+3^j)m
To find the displacement (→s)=→r2−→r1 =(4^i+3^j)−(^i+^j)=(3^i+2^j)m
To find angle between →F and →s: We know, ¯A.¯B=ABcosθ ⇒cosθ=¯A.¯BAB Similarly, cosθ=→F.→s|F||s| =(2^i−3^j+^k).(3^i+2^j)√42+32+12√32+22=6−6√26√13=0 Since, cosθ=0⇒θ=90o ⇒→F⊥→s Since force and displacement are perpendicular to each other the work done is equal to zero.