MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Work Done, Varying Force and Path

A constant fo...

Question

A constant force $\to F = (4^i - 6^j + 8^k) N$ acts on an object of mass of 4 kg. Calculate the work done in moving it from x = 0 to x = 10 m.

Open in App

Solution

$\to F = 4 i - 6 j + 8 k$

And displacement is $\to s = 10 i$

Hence, work done $W = \to F . \to s = (4 i - 6 j + 8 k) . (10 i)$

$⟹ W = 40 J$

Suggest Corrections

thumbs-up

0

Similar questions

Q. A position dependent force

F = 7 - 2 x + 3 x^{2}

N acts on a small object of mass 2kg to displace it from

x = 0

x = 5 m

. The work done in joules is-

F

acting on an object varies with distance

x

as shown in the figure.
The work done by the force in moving the object from

x = 0

x = 8 m

Q. A position-dependent force

F = 4 x^{3} + 3 x^{2} + 2 x - 4

newton acts on a small body of mass

2 k g

and displaces it from

x = 0

x = 2 m

. Calculate the work done.

Q. A position-dependent force

f = 7 - 2 x + 3 x^{2}

newton acts on a small body of mass

2

kg and displaces from

x = 0

x = 5

. Calculate the work done by the force.

F

is acting on an object varies with distance

x

is shown in the figure given below. The force is in

N

x

m

. The work done by the force in moving the object from

x = 0 to x = 6 m

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

So You Think You Know Work?

PHYSICS

Watch in App

explore_more_icon

Explore more

Work Done, Varying Force and Path

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon