Question

A constant pressure air thermometer gives a reading of 60 units of volume when immersed in ice cold water and 80 units in a boiling liquid. The temperature of boiling liquid is

• A. ${81}^{\circ }C$
• B. ${91}^{\circ }C$
• C. ${46}^{\circ }C$
• D. ${27}^{\circ }C$

Answer 1

The correct option is B ${91}^{\circ }C$

Given,

$V_1=60$

$V_2=80$

$T_1=0^{\circ }C$

According to Charle's Law

$\frac{V_1}{T_1}=\frac{V_2}{T_2}$

$\frac{60}{0+273}=\frac{80}{T+273}$

$60(T+273)=21840$

$60T+16380=21840$

$60T=21840-16380=5460$

$T={91}^{\circ }C$

Hence, option (B) is correct option