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Question

A constant retarding force of 50 N is applied to a body of mass 20 kg moving initially with a speed of 15 ms1. How long does the body take to stop?

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Solution

Retarding force, F=50N
Mass of the body, m=20kg
Initial velocity of the body, u=15m/s
Final velocity of the body, v=0

Using Newtons second law of motion, the acceleration (a) produced is given by:
F=ma
50=20 ×a
a=50/20=2.5m/s2
Using the first equation of motion, the time (t) taken by the body to come at rest
v=u+at
t=u/a=15/2.5=6s

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