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Question

A constant temperature and volume X decomposes as,
2X(g)3Y(g)+2Z(g)
PX is the partial pressure of X.
Observation No.Time (min)PX(in mm Hg)
1 0 800
2 100 400
3 200 200
(i) What is the order of the reaction with respect to X?
(ii) Find the rate constant.
(iii) Find the time for 75% completion of the reaction.
(iv) Find the total pressure when pressure of X is 700 mm Hg.

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Solution

(i) Data shows that half life of the reaction is constant, i.e., 100 min; hence, it is a first order reaction.
(ii) k=0.693t1/2=0.693100=6.93×103min1
(iii) t75, i.e., t3/4=2×t1/2=2×100=200 min
(iv) 2X(g)3Y(g)+2Z(g)
t=080000dt8002X3X2X
Total pressure =8002X+3X+2X=800+3X ...(i)
8002X=700
X=50
Total pressure =800+3×50=950 mm Hg

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