Question

A constant temperature, the equilibrium constant $\left(K_p\right)$ for the decomposition reaction $N_2{O}_4\rightleftharpoons 2N{O}_2$ is expressed by $K_p=\left(4x^{2}p\right)/(1-x^2)$, where $p=$ pressure and $x=$ extent of decomposition. Which one of the following statements is true?

• A. $K_p$ increases with increase in p
• B. $K_p$ increases with increase in x
• C. $K_p$ increases with decrease in x
• D. $K_p$ remains constant with change in p and x

Answer 1

Answer: (D)

$K_p$ remains constant with change in p and x

A constant temperature, the equilibrium constant $\left(K_p\right)$ for the decomposition reaction $N_2{O}_4\rightleftharpoons 2N{O}_2$ is expressed by $K_p=\left(4x^{2}p\right)/(1-x^2)$, where $p=$ pressure and $x=$ extent of decomposition. $K_p$ remains constant with change in p and x. The value of the equilibrium constant is independent of the partial pressure or degree of dissociation.