Question

A constant torque of 500Nm turns a wheel of moment of inertia 100kg m^2 about an axis through its centre. Find the gain in angular velocity in 2 seconds.

Answer 1

We know torque(τ) =moment of inertia(I)*angular acceleration(α)
I=100kgm^2
τ=500Nm
so α=τ/I=500/100 rad s^(-2)=5rad s^(-2
𐤃t=2s
α=change in angulat velocity/change in time
𐤃ω=α*𐤃t=5*2=10 rad s^(-1)
Answer=10 rad s^(-1)​​​​​​​