A constant voltage V0 - 12V is applied to a potential divider of resistance R - 4- connected to an ideal ammeter - A constant resistor r - 2 - is connected to a sliding contact of the potential divisor as shown - Find the minimum current measured by ammeter-

The correct option is A zero #10; [ #10; R_ eq = rx r+x #160;; ...

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Standard XII

Physics

Multiplication & Division of Errors

A constant vo...

Question

A constant voltage $V_{0}$ $(= 12 V)$ is applied to a potential divider of resistance $R (- 4 Ω)$ connected to an ideal ammeter . A constant resistor $r (= 2 Ω)$ is connected to a sliding contact of the potential divisor ( as shown ) . Find the minimum current measured by ammeter.

zero

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Solution

The correct option is A zero
$\begin{matrix} R_{e q} = \frac{r x}{r + x} i = \frac{V_{0} (r + x)}{r x} = \frac{12 (2 + x)}{2 x} = \frac{6 (2 + x)}{x} = \frac{d i}{d x} = \frac{6 x - 6 (2 + x)}{x^{2}} = \frac{- 12}{x^{2}} ∴ I_{min} = 0 H e n c e, o p t i o n A i s c o r r e c t a n s w e r . \end{matrix}$

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A constant voltage V0(=12V) is applied to a potential divider of resistance R(−4Ω) connected to an ideal ammeter . A constant resistor r(=2Ω) is connected to a sliding contact of the potential divisor ( as shown ) . Find the minimum current measured by ammeter.

The correct option is A zero Req=rxr+xi=V0(r+x)rx=12(2+x)2x=6(2+x)x=didx=6x−6(2+x)x2=−12x2∴Imin=0Hence,optionAiscorrectanswer.

A constant voltage $V_{0}$ $(= 12 V)$ is applied to a potential divider of resistance $R (- 4 Ω)$ connected to an ideal ammeter . A constant resistor $r (= 2 Ω)$ is connected to a sliding contact of the potential divisor ( as shown ) . Find the minimum current measured by ammeter.