A constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at 0- C and 100- C respectively- When the pressure reading is 60 cm of mercury- the temperature isA- 25- CB- 40- CC- 12- CD- 12-5- C

The correct option is A 25°C Here p_0 = 50 cm, p_100 = 90 cm , p_t = 60 cm t = p_t p_0/p_100 p_0× 100 = (60 50) × 100/(90 50) = 25^∘ ...

You visited us 3 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Chemistry

Introduction

A constant vo...

Question

At constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at $0^{\circ}$ C and $100^{\circ}$ C respectively. When the pressure reading is 60 cm of mercury, the temperature is

25°C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

40°C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12°C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

12.5°C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is
A
25°C
$\frac{t_{c} - t_{0}}{t_{100} - t_{0}} = \frac{p_{c} - p_{0}}{p_{100} - p_{0}};$
$w h e r e p_{c} = p r e s s u r e a t u n k n o w n t e m p e r a t u r e, t_{c} = u n k n o w n t e m p e r a t u r e, p_{100} = p r e s s u r e a t 100^{0} c,$
$p_{0} = p r e s s u r e a t 0^{0} c, t_{0} = t e m p e r a t u r e a t 0^{0} c$

$\frac{t_{c} - 0}{100 - 0} = \frac{60 - 50}{90 - 50}$
$\frac{t_{c}}{100} = \frac{60 - 50}{90 - 50} \Rightarrow \frac{10}{40}$
$t_{c} = \frac{1}{4} \times 100 \Rightarrow 25^{0} c$
$t_{c} = 25^{0} c$
Hence, the correct option is
A

Suggest Corrections

Similar questions

Q. A constant volume gas thermometer shows pressure readings of

50 c m

and

90 c m

of mercury at

0^{\circ} C,

100^{\circ} C

respectively. The temperature of the bath when pressure reading is

60 c m

of mercury, is:

Q. A constant volume gas thermometer shows pressure readings at

50 c m

and

90 c m

of mercury at

0^{\circ} C

and

100^{\circ} C

respectively. What is the temperature on gas scale when pressure reading is

60 c m

of mercury?

Q. A constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at 0

^{0} C

and 100

^{0} C

respectively. When the pressure reading is 60 cm of mercury, the temperature is:-

Q. The readings of a thermometer at

0^{\circ} C

and

100^{\circ} C

are

50 c m

and

75 c m

of mercury column respectively. Find the temperature at which its reading is

80 c m

of mercury column?

Q. The pressure of air in the bulb of a constant volume gas thermometer at

0^{\circ}

C and

100^{\circ}

C are 73.00 cm and 100 cm of mercury respectively. Calculate the pressure at room temperature

20^{\circ}

Join BYJU'S Learning Program

At constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at 0∘C and 100∘C respectively. When the pressure reading is 60 cm of mercury, the temperature is

The correct option is A 25°C tc−t0t100−t0=pc−p0p100−p0;wherepc=pressureatunknowntemperature,tc=unknowntemperature,p100=pressureat1000c,p0=pressureat00c,t0=temperatureat00c tc−0100−0=60−5090−50tc100=60−5090−50⇒1040tc=14×100⇒250ctc=250cHence, the correct option is A

At constant volume gas thermometer shows pressure reading of 50 cm and 90 cm of mercury at $0^{\circ}$ C and $100^{\circ}$ C respectively. When the pressure reading is 60 cm of mercury, the temperature is