Question

A constant volume gas thermometer shows pressure reading of $50cm$ and $90cm$ of mercury at $0^{\circ }C$ and ${100}^{\circ }C$ respectively. When the pressure reading is $60cm$ of mercury, the temperature is

• A. ${25}^{\circ }C$
• B. ${15}^{\circ }C$
• C. ${12.5}^{\circ }C$
• D. ${40}^{\circ }C$

Answer 1

The correct option is A ${25}^{\circ }C$

We know that: $T=\frac{P_t-P_0}{P_{100}-P_0}\times 100$

Given: $P_0=50cmofHg,$
$P_{100}=90cmofHg,P_T=60cm$

$T=\frac{P_t-P_0}{P_{100}-P_0}\times 100$

$T=\frac{60-50}{90-50}\times 100$

$T=\frac{10}{40}\times 100$

$={25}^{\circ }C$
Final answer (a)