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Question

A container contains 0.25 kg of a liquid at its boiling temperature. If the latent heat of fusion for the liquid is 500 Joules/ kg and the latent heat of vaporization for the liquid is 1000 Joules/ Kg. How much heat must be added to the liquid to boil all of the liquid away?

A
125J
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B
2000J
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C
4000J
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D
0.50J
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E
250J
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Solution

The correct option is E 250J
Mass of liquid to be boiled m=0.25kg
Latent heat of vaporization of liquid Hv=1000 J/kg
Thus heat required to boil the liquid Q=mHv=0.25×1000=250J

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