A container contains $14$ L $613$ mL of milk. Another container contains $2$ L $675$ mL more milk than the previous container. How much of milk is contained in the second container?

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Solution

Amount of milk conatined in first container
= $14$ L $613$ mL
= $14613$ mL $(1 L = 1000 mL)$

Amount of milk that second container contains more
= $2$ L $675$ mL
= $2675$ mL $(1 L = 1000 mL)$

Therefore, amount of milk in second container
= $14613$ mL + $2675$ mL
= $17288$ mL
= $17000 + 288$ mL
= $17$ L $288$ mL $(1000 mL = 1 L)$

Hence, (a) is correct.

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A container contains 14 L 613 mL of milk. Another container contains 2 L 675 mL more milk than the previous container. How much of milk is contained in the second container?

A container contains $14$ L $613$ mL of milk. Another container contains $2$ L $675$ mL more milk than the previous container. How much of milk is contained in the second container?