A container contains $15 L$ of oil. $345 mL$ of oil drained out of the container due to leakage. How much oil is remaining in the container

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Solution

Total oil in the container = $15 L$
drained oil due to leakage = $345 mL$ = $0.345 L$
(since, $1 L = 1000 mL$ )
$S o, t h e r e m a i n i n g o i l i n t h e c o n t a i n e r = 15.000 - 0.345 = 14.655 L$
Hence, $14 L$ and $655 mL$ of oil is remaining in the container.

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A container contains 15L of oil. 345mL of oil drained out of the container due to leakage. How much oil is remaining in the container

Total oil in the container = 15Ldrained oil due to leakage = 345mL = 0.345L (since, 1L=1000mL)So,theremainingoilinthecontainer=15.000-0.345=14.655LHence, 14L and 655mL of oil is remaining in the container.

A container contains $15 L$ of oil. $345 mL$ of oil drained out of the container due to leakage. How much oil is remaining in the container

Total oil in the container = $15 L$
drained oil due to leakage = $345 mL$ = $0.345 L$
(since, $1 L = 1000 mL$ )
$S o, t h e r e m a i n i n g o i l i n t h e c o n t a i n e r = 15.000 - 0.345 = 14.655 L$
Hence, $14 L$ and $655 mL$ of oil is remaining in the container.