wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A container has 30 L of water. If 3 L of water is replaced by 3 L of spirit and this operation is repeated twice, what will be the quantity of water in the new mixture?

A
24 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
23 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
24.3 L
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
23.3 L
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 24.3 L
Here,
We apply the formula,
Quantity of pure liquid left
=y(1xy)nunits
Here, y =Quantity of pure liquid
x =Quantity replaced
So, quantity of water =30
(1330)2=30(1110)2=30×(910)2=30×0.81=24.3L


flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Introduction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon