A container has two layers of immiscible liquids 1 and 2 with refractive indices 1.5 and 4/3 respectively. What is apparent position of an object placed at the bottom of the vessel. Thickness of the layers are 3cm and 8cm respectively?
A
6cm below the liquid 2 - air interface.
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B
8cm below the liquid 2 - air interface.
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C
8cm below the liquid 1 - liquid 2 interface.
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D
6cm below the water - air interface.
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Solution
The correct option is B8cm below the liquid 2 - air interface. Using Image shift in glass slab formula,
Shift of position of object due to liquids of refractive indices μ1,μ2 and thickness d1,d2 is d1(1−1μ1)+d2(1−1μ2)
Here μ1=32,μ2=43 and thickness d1=3cm,d2=8cm
So shift = 3(1−23)+8(1−34)=3cm upwards from bottom of the container.
Hence final position from air-liquid 2 interface is 8+3−3=8cm below it