A container having slightly conducting walls contains air. The initial temperature and volume are 47oC (equal to the temperature of the surrounding) and 400cm3 respectively. Find the rise in temperature if the gas is compressed to 200cm3in a very short time. Take γ=1.4[20.4=1.3]
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Solution
When the gas is compressed in a short time, the process is adiabatic. Thus, T2Vγ−12=T1Vγ−12 or T2=T1(V1V2)γ−1=(320K)×[400200]0.4=416K Rise in temperature =T2−T1=96K.