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Question

A container having slightly conducting walls contains air. The initial temperature and volume are 47oC (equal to the temperature of the surrounding) and 400cm3 respectively. Find the rise in temperature if the gas is compressed to 200cm3 in a very short time. Take γ=1.4 [20.4=1.3]

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Solution

When the gas is compressed in a short time, the process is adiabatic. Thus,
T2Vγ12=T1Vγ12
or T2=T1(V1V2)γ1=(320K)×[400200]0.4=416K
Rise in temperature =T2T1=96K.

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