A container holds 500 mL of $C O_{2}$ at $20^{\circ} C$ and 742 torr. What will be the volume of the $C O_{2}$ if the pressure is increased to 795 torr?

400 mL of $C O_{2}$

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227 mL of $C O_{2}$

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150 mL of $C O_{2}$

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467 mL of $C O_{2}$

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Solution

The correct option is D
467 mL of $C O_{2}$

$P_{1} = 742 t o r r, P_{2} = 795 t o r r V_{1} = 500 m L, V_{2} = ? T_{1} = 20^{\circ} C + 273 = 293 K T_{2} = 20^{\circ} C + 273 = 293 K P_{1} V_{1} = P_{2} V_{2} V_{2} = \frac{P_{1} V_{1}}{P_{2}} V_{2} = \frac{742 \times 500}{795} = 467 m L C O_{2}$

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