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Finding Unknown Using Formula of Volume of Rectangular Box

A container h...

Question

A container holds 500 $m L$ of $C O_{2}$ at $20^{o} C$ and 742 $t o r r$ . What will be the volume of the $C O_{2}$ if the pressure is increased to 795 $t o r r$ ?

567

m L

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483

m L

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467

m L

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345

m L

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Solution

The correct option is C 467 $m L$
$P_{1} = 742 t o r r$
$P_{2} = 795 t o r r$
$V_{1} = 500 m L$
$V_{2} = ?$
$T_{1} = 20 ° C + 273 = 293 K$
$P_{1} V_{1} = P_{2} V_{2}$
$V_{2} = P_{1} V_{1} / P_{2} V_{2} = 742 t o r r x 500 m L / 795 t o r r = 467 m L C O_{2}$

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A container holds 500 mL of CO2 at 20oC and 742 torr. What will be the volume of the CO2 if the pressure is increased to 795 torr?

The correct option is C 467 mLP1=742torr P2=795torr V1=500mL V2=? T1=20°C+273=293K P1V1=P2V2V2=P1V1/P2V2=742torrx500mL/795torr=467mLCO2

A container holds 500 $m L$ of $C O_{2}$ at $20^{o} C$ and 742 $t o r r$ . What will be the volume of the $C O_{2}$ if the pressure is increased to 795 $t o r r$ ?

The correct option is C 467 $m L$
$P_{1} = 742 t o r r$
$P_{2} = 795 t o r r$
$V_{1} = 500 m L$
$V_{2} = ?$
$T_{1} = 20 ° C + 273 = 293 K$
$P_{1} V_{1} = P_{2} V_{2}$
$V_{2} = P_{1} V_{1} / P_{2} V_{2} = 742 t o r r x 500 m L / 795 t o r r = 467 m L C O_{2}$