A container holds $600$ litres of air at a pressure of $2$ atmospheres. If the pressure on the gas is increased to $5$ atmospheres, what will its volume become?
(Assume that the temperature remains constant)

Open in App

Solution

The final volume is given as,

$P_{1} V_{1} = P_{2} V_{2}$

$2 \times 600 = 5 \times V_{2}$

$V_{2} = 240 l i t r e s$

Thus, the final volume is $240 l i t r e s$ .

Suggest Corrections

Similar questions

Q. A sample of a gas occupies

10

litre under a pressure of

1

atmosphere. What will be its volume if the pressure is increased to

2

atmosphere?

Assume that the temperature of the gas sample does not change.

Q. If the mean free path of a gas is

λ

at one atmospheric pressure, then its value at 5 atmospheric pressure will be (temperature is assumed to be constant)

A cylinder of 200 litres capicity contains a gas at 100 atmospheric pressure. How many flasks of $200 c m^{3}$ capacity can be filled from it at 1 atmosphere pressure, temperature remaining constant?

Q. A gas is enclosed in a vessel at a constant temperature at a pressure of 2.5 atmospheres and a volume of 4 litres. Due to leak in the vessel, after some time the pressure is reduced to 2 atmospheres. As a result :

Q. A steel cylinder of internal volume 20 litres is filled with hydrogen at 29 atmospheric pressure. If hydrogen is used to fill a balloon at 1.25 atmospheric pressure at the same temperature, what volume will the gas occupy?

Join BYJU'S Learning Program

A container holds 600 litres of air at a pressure of 2 atmospheres. If the pressure on the gas is increased to 5 atmospheres, what will its volume become? (Assume that the temperature remains constant)

The final volume is given as, P1V1=P2V2 2×600=5×V2 V2=240litres Thus, the final volume is 240litres.

A container holds $600$ litres of air at a pressure of $2$ atmospheres. If the pressure on the gas is increased to $5$ atmospheres, what will its volume become?
(Assume that the temperature remains constant)

The final volume is given as,

$P_{1} V_{1} = P_{2} V_{2}$

$2 \times 600 = 5 \times V_{2}$

$V_{2} = 240 l i t r e s$

Thus, the final volume is $240 l i t r e s$ .