Question

A container holds a mixture of two different gases. The oxygen in a container exerts $80$ mm Hg of pressure on the inside of the container. The total pressure inside the container is $120$ mm Hg. What is the pressure of the other gas in the container?

• A. $40$ mm Hg
• B. $0.67$ mm Hg
• C. $200$ mm Hg
• D. $1.5$ mm Hg
• E. $80$ mm Hg

Answer 1

The correct option is A $40$ mm Hg

According to Dalton's law of partial pressure, the total pressure exerted by the gaseous mixture of non reacting gases is the sum of partial pressures of the individual gases.

$P_{total}=P_{O_2}+P_{other}$

$120=80+P_{other}$

$\Rightarrow P_{other}=(120-80)=40mmHg$