Question

A container is $12m$ long, $8m$ wide and $5m$ high. How many cubical parcels can be accommodated in the container, if each parcel requires $8m^3$ of space?

Answer 1

Volume of container $=12\times 8\times 5=480m^3$

Space required by each parcel $=8m^3$

Therefore,

No. of parcels can be accomodated in the container $=\frac{480}{8}=60$