A container of $5$ liter has a gas at pressure of $0.8 m$ column of $H g$ . This is joined to an evacuated container of $3$ liter capacity. The resulting pressure will be :- (At constant t temperature )

\frac{4}{3} m

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0.5 m

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2.0 m

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\frac{3}{4} m

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Solution

The correct option is C $0.5 m$
Let us say, the final pressure becomes 'P'.
Since temperature, 'T' is constant
Case I:
applying ideal gas equation
$P V = n R T$
$0.8 \times 5 = n R T$ …….. $(1)$
Case II:
$P \times (5 + 3) = n R T$ …….. $(2)$
Dividing $(1)$ & $(2)$
$\frac{0.8 \times 5}{P \times 8} = 1$
$\Rightarrow P = \frac{0.8 \times 5}{8}$
$\Rightarrow P = 0.5$ m of Hg.

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A container of 5 liter has a gas at pressure of 0.8 m column of Hg. This is joined to an evacuated container of 3 liter capacity. The resulting pressure will be :- (At constant t temperature )

The correct option is C 0.5mLet us say, the final pressure becomes 'P'.Since temperature, 'T' is constantCase I:applying ideal gas equationPV=nRT0.8×5=nRT ……..(1)Case II:P×(5+3)=nRT ……..(2)Dividing (1) & (2)0.8×5P×8=1⇒P=0.8×58⇒P=0.5m of Hg.

A container of $5$ liter has a gas at pressure of $0.8 m$ column of $H g$ . This is joined to an evacuated container of $3$ liter capacity. The resulting pressure will be :- (At constant t temperature )