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Question

A container of fixed volume have a mixture of one mole of hydrogen and one mole of helium in equilibrium at temperature T. Assuming the gases are ideal, the correct statement(s) is/are

A
The average energy per mole of the gas mixture is 2RT
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B
The ratio of speed of sound in the gas mixture to that in helium gas is 65.
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C
The ratio of the RMS speed of helium atoms that of hydrogen molecules is 12
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D
The ratio of the RMS speed of helium atoms to that of hydrogen molecules is 12
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Solution

The correct option is D The ratio of the RMS speed of helium atoms to that of hydrogen molecules is 12
We know that internal energy of the ideal gas is given by,

U=nfRT2

where, f degree of freedom
n number of moles

So, Energy per mole

E=n1f1RT2+n2f2RT2n1+n2

From the data given in the question,

E=1×5×RT+1×3×RT1+1E=4RT

Now, average energy per mole, Eav=E2=2RT

Hence, option (a) is correct.

γmix=n1Cp1+n2Cp2n1Cv1+n2Cv2=1×7R2+1×5R21×5R2+1×3R2=32

[CpCv=R, Cv=fR2]

Mmix=n1M1+n2M2n1+n2=1×2+1×41+1=3

Speed of sound v=γRTM

At same temperature,

v γM

So,
vmixvHe=γmixγHe×μHeμmix=3×32×5×43=65

Hence, option (b) is correct.

RMS speed , vrms=3RTM

At same temperature

vrms1M

So, vHevH2=MH2MHe=24=12=12

Hence, option (c) is wrong and option (d) is correct.
Why this question?

Concept involved -(1)Internal Energy of ideal gas
(2) Speed of sound and RMS speed.

Importance in JEE -Asked in advance 2015

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