A container shown in figure contains a liquid to a depth H, and of density ρ. The gauge pressure at point P is
A
ρgH2+P0
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B
ρgH2
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C
ρgH2cosθ
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D
ρgHcosθ2
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Solution
The correct option is BρgH2 Formula used: Pgauge=Ptotal−Patm,P=ρgh
Given :h=H2
From the diagram we can see that depth of point P is H2
Gauge pressure will be equal to Pgauge=(Patm+ρgh)−Patm=ρgh h=H2
Gauge pressure is Hρg2