A container truck goes from Mumbai to Bangalore with an average speed of $50 k m h r^{- 1}$ . The journey takes $20 h o u r s$ . It returns from Bangalore to Mumbai on the same road with an average speed of $40 k m h r^{- 1}$ . What was the average speed of the container during the roundtrip?

44 m s^{- 1}

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44 k m h r^{- 1}

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4.44 m s^{- 1}

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44 m s^{- 1}

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Solution

The correct option is B $44 k m h r^{- 1}$
Given:
average speed while going $= 50 k m h r^{- 1}$ ,
time taken for going $= 20 h$ , average speed while returning $= 40 k m h r^{- 1}$ .
Calculating the distance between the two cities.
Speed = $\frac{d i s t a n c e}{t i m e}$
Or Distance = speed $\times$ time = $50 k m h^{- 1} \times 20 h$ = $1000 k m$
This will be the constant distance between the two cities even for return journey.
Then, total distance = $1000 + 1000 = 2000 k m$
For return journey,
time = $\frac{d i s t a n c e}{s p e e d}$ = $\frac{1000}{40} = 25 h$ .
Total time $T = 20 + 25 = 45 h .$
Then,
Average speed = $\frac{t o t a l d i s t a n c e}{t o t a l t i m e}$
= $\frac{2000}{45} = 44.4 k m h^{- 1}$

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A container truck goes from Mumbai to Bangalore with an average speed of 50 kmhr−1. The journey takes 20 hours. It returns from Bangalore to Mumbai on the same road with an average speed of 40 kmhr−1. What was the average speed of the container during the roundtrip?

A container truck goes from Mumbai to Bangalore with an average speed of $50 k m h r^{- 1}$ . The journey takes $20 h o u r s$ . It returns from Bangalore to Mumbai on the same road with an average speed of $40 k m h r^{- 1}$ . What was the average speed of the container during the roundtrip?