A continuous and differentiable function y=f(x) is such that its graph cuts line y=mx+c at n distinct points. Then the minimum number of points at which f′′(x)=0 is/are
A
n−1
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B
n−3
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C
n−2
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D
cannot say
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Solution
The correct option is Cn−2 y=f(x) is a differentiable and continuous curve. The line cuts this curve n times so leave end cuts of curve and rest intersecting must be infection point. thus at least n−2 points are inflection points.