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Methods of Plastic Analysis - Kinematic Method - Part 1

A continuous ...

Question

A continuous beam with constant EI is shown in the figure. Collapse load for this beam will be equal to _______.

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Solution

For left span,
$\frac{W L}{2} θ = 2 M_{P} (θ + θ) + M_{P} θ$
$\Rightarrow W = \frac{10 M_{P}}{L}$

For right span,
$W \times \frac{L}{3} \times 2 θ = M_{P} (θ + 2 θ) + M_{P} θ$
$\Rightarrow W = \frac{6 M_{P}}{L}$

$H e n c e, \frac{6 M_{P}}{L} w i l l b e t h e c o l l a p s e l o a d .$

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