You visited us 1 times! Enjoying our articles? Unlock Full Access!

A continuous ...

Question

A continuous time signal $x (t) = 4 cos (200 π t) + 8 cos (400 π t)$ , where $t$ is in seconds, is the input to a linear time invariant (LTI) filler with the impulse response
$h (t) = ⎧ ⎪ ⎨ ⎪ ⎩ \begin{matrix} \frac{2 sin (300 π t)}{π t}, t \neq 0 600, t = 0 \end{matrix}$
Let $y (t)$ be the output of this filter. The maximum value of $| y (t) |$ is
8

Open in App

Solution

The correct option is A 8
$x (t) = 4 cos 200 π t + 8 cos 400 π t$
$h (t) = \frac{2 sin 300 π t}{π t} F . T \leftrightarrow$
So, $y (t) = 8 cos 200 π t$
$∴ | y (t) |_{max} = 8$

Suggest Corrections

Similar questions

P_{1}

P_{2}

P_{3}

R_{1}

R_{2}

R_{3}

R_{4}

Properties:

P_{1}

P_{2}

P_{3}

Relations:

R_{1} : y (t) = t^{2} x (t)

R_{2} : y (t) = t | x (t) |

R_{3} : y (t) = | x (t) |

R_{4} : y (t) = x (t - 5)

y (t) |_{t = 5}

y (t) = 0.5 x (t - t_{d} + T) + x (t - t_{d}) + 0.5 x (t - t_{d} - T)

H (ω)

y (t) = \int_{- \infty}^{t - 10} e^{- (t - 5 - τ)} x (τ) d (τ)

h (t) = {\begin{matrix} 3 & f o r 0 \leq t \leq 3 o & o t h e r w i s e \end{matrix}

Join BYJU'S Learning Program