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Question

A contract on construction job specifies a penalty for delay of completion beyond a certain date as follows: Rs. 200 for the first day, Rs. 250 for the second day, Rs. 300 for the third day etc., the penalty for each succeeding day being Rs. 50 more than for the preceding day. How much money the contractor has to pay as penalty, if he has delayed the work by 30 days?

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Solution

The money the contractor has to pay as a penalty forms an A.P.

We know,

Sn=n2[2a+(n1)d] ............ (Sum of n terms)

a= First term
d= Common difference
n= number of terms

Here,
a=200,d=50 and n=30

S30=302(400+50×29)=27750

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