Question

A contractor undertook to do a certain piece of work in $9$ days. He employed certain number of men, but $6$ of them being absent from the very first day, the rest could finish the work in $15$ days. The number of men originally employed were

• A. $12$
• B. $15$
• C. $18$
• D. $24$

Answer 1

Answer: (B)

$15$

Let there be $x$ men at the begining less men, more days
$\therefore$ $15:9::x:(x-6)$ $\Rightarrow$ $15(x-6)=9x$
$\Rightarrow$ $6x=90$ $\Rightarrow$ $x=15$